5/4x=2x^2

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Solution for 5/4x=2x^2 equation: 


x in (-oo:+oo)

(5/4)*x = 2*x^2 // - 2*x^2

(5/4)*x-(2*x^2) = 0

(5/4)*x-2*x^2 = 0

5/4*x-2*x^2 = 0

DELTA = (5/4)^2-(-2*0*4)

DELTA = 25/16

DELTA > 0

x = ((25/16)^(1/2)-5/4)/(-2*2) or x = (-(25/16)^(1/2)-5/4)/(-2*2)

x = 0 or x = 5/8

x in { 0, 5/8 }

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